Lesson 10The Distributive Property (Part 2)

Learning Goal

Let’s use rectangles to understand the distributive property with variables.

Learning Targets

  • I can use a diagram of a split rectangle to write different expressions with variables representing its area.

Lesson Terms

  • equivalent expressions
  • term

Warm Up: Possible Areas

Problem 1

A rectangle has a width of 4 units and a length of units. Write an expression for the area of this rectangle.

Problem 2

What is the area of the rectangle if is:

  1. 3 units?

  2. 2.2 units?

  3. unit?

Problem 3

Could the area of this rectangle be 11 square units? Why or why not?

Activity 1: Partitioned Rectangles When Lengths are Unknown

Problem 1

Here are two rectangles. The length and width of one rectangle are 8 and 5. The width of the other rectangle is 5, but its length is unknown so we labeled it . Write an expression for the sum of the areas of the two rectangles.

Two rectangles. One with dimensions 5 by x. The other is 8 by 5.

Problem 2

The two rectangles can be composed into one larger rectangle as shown. What are the width and length of the new, large rectangle?

A figure of a smaller  rectangle within a larger one. The width is divided into segments labeled x and 8. The height is 5.

Problem 3

Write an expression for the total area of the large rectangle as the product of its width and its length.

Activity 2: Areas of Partitioned Rectangles

Problem 1

For each rectangle, write expressions for the length and width and two expressions for the total area. Record them in the table. Check your expressions in each row with your group and discuss any disagreements.

Six different sized rectangles labeled A, B, C, D, E, and F.  Rectangle A is partioned by a vertical line segment into two smaller rectangles. The vertical side is labeled 3 and the top horizontal side lengths are labeled "a" and 5.  Rectangle B is partitioned by a vertical line segment into two smaller rectangles. The vertical side is labeled one third and the top horizontal side lengths are labeled 6 and x. Rectangle C is partitioned by 2 vertical line segments into three equally sized rectangles. The vertical side is labeled r and the top horizontal side lengths are each labeled 1. Rectangle D is partitioned by 3 vertical line segments into 4 equally sized rectangles. The vertical side is labeled 6, and the top horizontal side lengths are each labeled 4. Rectangle E is partitioned by a vertical line segment into two smaller rectangles. The vertical side is labeled m and the top horizontal side lengths are labeled 6 and 8. Rectangle F is partitioned by a vertical line segment into two smaller rectangles. The vertical side is labeled 5 and the top horizontal side lengths are labeled 3 x and 8.

width

length

area as a product of
width times length

area as a sum of the areas
of the smaller rectangles

Are you ready for more?

Problem 1

Here is an area diagram of a rectangle.

An area diagram of a rectangle. The columns are labeled y and z. The rows are labeled w and x. Box yw is A, yx is 18, zw is 24, and zx is 72
  1. Find the lengths , , , and , and the area . All values are whole numbers.

  2. Can you find another set of lengths that will work? How many possibilities are there?

Lesson Summary

Here is a rectangle composed of two smaller rectangles A and B.

A rectangle is partitioned by a vertical line segment creating two smaller rectangles, A and B. Rectangle A has a vertical side length of 3 and horizontal side length of 2. Rectangle B has a horizontal side length of x.

Based on the drawing, we can make several observations about the area of the rectangle:

  • One side length of the large rectangle is 3 and the other is , so its area is .

  • Since the large rectangle can be decomposed into two smaller rectangles, A and B, with no overlap, the area of the large rectangle is also the sum of the areas of rectangles A and B: or .

  • Since both expressions represent the area of the large rectangle, they are equivalent to each other. is equivalent to .

We can see that multiplying 3 by the sum is equivalent to multiplying 3 by 2 and then 3 by and adding the two products. This relationship is an example of the distributive property.